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Solve Using the Addition and Multiplication Principles 15x−24>3(4x−11)15 x-24>3(4 x-11) A) {x∣x≤−3}\{x \mid x \leq-3\}

Question 161

Multiple Choice

Solve using the addition and multiplication principles.
- 15x−24>3(4x−11) 15 x-24>3(4 x-11)


A) {x∣x≤−3}\{x \mid x \leq-3\}
B) {x∣x>−3}\{x \mid x>-3\}
C) {x∣x<−3}\{x \mid x<-3\}
D) {x∣x≥−3}\{x \mid x \geq-3\}

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