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A Balloon in the Shape of a Sphere Is Deflating tt

Question 195

Multiple Choice

A balloon in the shape of a sphere is deflating. Given that tt represents the time, in minutes, since it began losing air, the radius of the balloon (in cm\mathrm{cm} ) is r(t) =20tr(t) =20-\mathrm{t} . Let the equation V(r) =43πr3\mathrm{V}(\mathrm{r}) =\frac{4}{3} \pi \mathrm{r}^{3} represent the volume of a sphere of radius rr . Find and interpret (Vr) (t) (\mathrm{V} \circ \mathrm{r}) (\mathrm{t}) .


A) (Vr) (t) =2043π(20t) 3(V \circ r) (t) =20-\frac{4}{3} \pi(20-t) ^{3} ; this is the volume of the air lost by the balloon (in cm3\mathrm{cm}^{3} ) as a function of time (in minutes) .
B) (Vr) (t) =43π(20t) 3(V \circ r) (t) =\frac{4}{3} \pi(20-t) ^{3} ; this is the volume of the air lost by the balloon (in cm3) \left.\mathrm{cm}^{3}\right) as a function of time (in minutes) .
C) (Vr) (t) =43π(20t) 3(V \circ r) (t) =\frac{4}{3} \pi(20-t) ^{3} ; this is the volume of the balloon (in cm3) \left.\mathrm{cm}^{3}\right) as a function of time (in minutes) .
D) (Vr) (t) =43π(t20) 3(\mathrm{V} \circ \mathrm{r}) (\mathrm{t}) =\frac{4}{3} \pi(\mathrm{t}-20) ^{3} ; this is the volume of the balloon (in cm3\mathrm{cm}^{3} ) as a function of time (in minutes) .

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