The Length of the Diagonal of a Box Is Given $\mathrm{D}=\sqrt{\mathrm{L}^{2}+\mathrm{W}^{2}+\mathrm{H}^{2}}$

Multiple Choice

The length of the diagonal of a box is given by $\mathrm{D}=\sqrt{\mathrm{L}^{2}+\mathrm{W}^{2}+\mathrm{H}^{2}}$ where $\mathrm{L}, \mathrm{W}$ , and $\mathrm{H}$ are the length, width, and height of the box. Find the length of the diagonal, $\mathrm{D}$ , of a box that is $4 \mathrm{ft}$ long, $2 \mathrm{ft}$ high, and $4 \mathrm{ft}$ wide. Give the exact value.

A) $32 \mathrm{ft}$
B) $10 \mathrm{ft}$
C) $4 \sqrt{2} \mathrm{ft}$
D) $6 \mathrm{ft}$