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  2. Topic
    Mathematics
  3. Study Set
    Intermediate Algebra
  4. Exam
    Exam 8: Roots, Radicals, and Root Functions
  5. Question
    \(\sqrt{9} \cdot \sqrt{25}=\sqrt{9 \cdot 25}\)
Solved

9⋅25=9⋅25\sqrt{9} \cdot \sqrt{25}=\sqrt{9 \cdot 25}9​⋅25​=9⋅25​

Question 103

Question 103

True/False

9⋅25=9⋅25\sqrt{9} \cdot \sqrt{25}=\sqrt{9 \cdot 25}9​⋅25​=9⋅25​

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