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The Solution Set of the Inequality x2+9x+20≥0x^{2}+9 x+20 \geq 0 Is (−∞,−5]∪[−4,∞)(-\infty,-5] \cup[-4, \infty)

Question 258

Multiple Choice

The solution set of the inequality x2+9x+20≥0x^{2}+9 x+20 \geq 0 is (−∞,−5]∪[−4,∞) (-\infty,-5] \cup[-4, \infty) . Without doing any work, give the solution to x2+9x+20<0x^{2}+9 x+20<0 .


A) [−5,−4][-5,-4]
B) (−5,∞) (-5, \infty)
C) (−5,−4) (-5,-4)
D) (−∞,−5) ∪(−4,∞) (-\infty,-5) \cup(-4, \infty)

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