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The Half-Life of a Certain Radioactive Substance Is 36 Years t=0t=0

Question 19

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The half-life of a certain radioactive substance is 36 years. Suppose that at time t=0t=0 , there are 27 g27 \mathrm{~g} of the substance. Then after tt years, the number of grams of the substance remaining will be N(t) =\mathrm{N}(\mathrm{t}) = 27(1/2) t/3627(1 / 2) ^{t / 36} . How many grams of the substance will remain after 198 years?


A) 0.6 g0.6 \mathrm{~g}
B) 0.3 g0.3 \mathrm{~g}
C) 0.07 g0.07 \mathrm{~g}
D) 0.15 g0.15 \mathrm{~g}

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