Solve the Equation $\mathrm{e}^{\ln 3 x}=\mathrm{e}^{\ln (2 x+4)}$ A) $\{4\}$ B) $\{-4\}$ C) $\left\{-\frac{4}{5}\right\}$

Multiple Choice

Solve the equation. Use natural logarithms. When appropriate, give solutions to three decimal places unless otherwise indicated.
- $\mathrm{e}^{\ln 3 x}=\mathrm{e}^{\ln (2 x+4) }$

A) $\{4\}$
B) $\{-4\}$
C) $\left\{-\frac{4}{5}\right\}$
D) $\left\{\frac{4}{5}\right\}$