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Find the Center and Radius of the Circle Whose Equation x2+y2+12x+8y+52=81x^{2}+y^{2}+12 x+8 y+52=81

Question 60

Multiple Choice

Find the center and radius of the circle whose equation is given.
- x2+y2+12x+8y+52=81x^{2}+y^{2}+12 x+8 y+52=81


A) center: (4,6) (4,6) ; radius: 81
B) center: (6,4) (6,4) ; radius: 81
C) center: (6,4) (-6,-4) ; radius: 9
D) center: (4,6) (-4,-6) ; radius: 9

Correct Answer:

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