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Find a General Term for the Geometric Sequence 12,16,\frac{1}{2}, \frac{1}{6}, \ldots

Question 24

Multiple Choice

Find a general term for the geometric sequence.
- 12,16,\frac{1}{2}, \frac{1}{6}, \ldots


A) an=14n2a_{n}=\frac{1}{4 n-2}

B) an=13(12) n1a_{n}=\frac{1}{3}\left(\frac{1}{2}\right) ^{n-1}

C) an=12(13) n1\mathrm{a}_{\mathrm{n}}=\frac{1}{2}\left(\frac{1}{3}\right) ^{\mathrm{n}-1}

D) an=12(13) 1n\mathrm{a}_{\mathrm{n}}=\frac{1}{2}\left(\frac{1}{3}\right) ^{1-\mathrm{n}}

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