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Find a General Term for the Geometric Sequence 32,−16,…32,-16, \ldots A) an=32(12)n−1a_{n}=32\left(\frac{1}{2}\right)^{n-1}

Question 47

Multiple Choice

Find a general term for the geometric sequence.
- 32,−16,…32,-16, \ldots


A) an=32(12) n−1a_{n}=32\left(\frac{1}{2}\right) ^{n-1}

B) an=32(−12) n−1a_{n}=32\left(-\frac{1}{2}\right) ^{n-1}

C) an=32(−13) n−1a_{n}=32\left(-\frac{1}{3}\right) ^{n-1}

D) an=32(−2) n−1a_{n}=32(-2) ^{n-1}

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