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Given the Line-To-Ground Voltages Vag=2800,Vbg=290130V_{a g}=280 \angle 0^{\circ}, V_{b g}=290 \angle-130^{\circ}

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Given the line-to-ground voltages Vag=2800,Vbg=290130V_{a g}=280 \angle 0^{\circ}, V_{b g}=290 \angle-130^{\circ} , and Vcg=260110V_{c g}=260 \angle 110^{\circ} volts, calculate (a) the sequence components of the line-to-ground voltages, denoted VLg0,VLg1V_{\mathrm{L} g 0}, V_{\mathrm{L} g 1} , and VLg2V_{\mathrm{L} g 2} ; (b) line-to-line voltages Vab,VbcV_{a b}, V_{b c} , and VcaV_{c a} ; and (c) sequence components of the line-to-line voltages VLL0,VLL1V_{\mathrm{LL} 0}, V_{\mathrm{LL} 1} , and VLL2V_{\mathrm{LL} 2} . Also, verify the following general relation: VLL0=0,VLL1=3VLg1+30V_{\mathrm{LL} 0}=0, V_{\mathrm{LL} 1}=\sqrt{3} V_{\mathrm{L} g 1} \angle+30^{\circ} , and VLL2=3VLg230V_{\mathrm{LL} 2}=\sqrt{3} V_{\mathrm{L} g 2} \angle-30^{\circ} volts.

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