Solved

Find the Derivative Of $f(x)=\frac{x}{\cos 2 x}$
A) $f^{\prime}(x)=\frac{\cos 2 x+x \sin 2 x}{\cos ^{2} 2 x}=\sec 2 x+x \sec 2 x \tan 2 x$

Question 35

Multiple Choice

Find the derivative of $f(x) =\frac{x}{\cos 2 x}$ .

A) $f^{\prime}(x) =\frac{\cos 2 x+x \sin 2 x}{\cos ^{2} 2 x}=\sec 2 x+x \sec 2 x \tan 2 x$
B) $f^{\prime}(x) =\frac{\cos 2 x-x \sin 2 x}{\cos ^{2} 2 x}=\sec 2 x-x \sec 2 x \tan 2 x$
C) $f^{\prime}(x) =\frac{\cos 2 x-2 x \sin 2 x}{\cos ^{2} 2 x}=\sec 2 x-2 x \sec 2 x \tan 2 x$
D) $f^{\prime}(x) =\frac{\cos 2 x+2 x \sin 2 x}{\cos ^{2} 2 x}=\sec 2 x+2 x \sec 2 x \tan 2 x$

Find the Derivative Of f(x)=xcos⁡2xf(x)=\frac{x}{\cos 2 x}f(x)=cos2xx​ A) f′(x)=cos⁡2x+xsin⁡2xcos⁡22x=sec⁡2x+xsec⁡2xtan⁡2xf^{\prime}(x)=\frac{\cos 2 x+x \sin 2 x}{\cos ^{2} 2 x}=\sec 2 x+x \sec 2 x \tan 2 xf′(x)=cos22xcos2x+xsin2x​=sec2x+xsec2xtan2x

Multiple Choice

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Find the Derivative Of $f(x)=\frac{x}{\cos 2 x}$
A) $f^{\prime}(x)=\frac{\cos 2 x+x \sin 2 x}{\cos ^{2} 2 x}=\sec 2 x+x \sec 2 x \tan 2 x$

Correct Answer:
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