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Find the Equation of the Line Tangent to the Curve f(x)=lnx2f(x)=\ln x^{2}

Question 45

Multiple Choice

Find the equation of the line tangent to the curve f(x) =lnx2f(x) =\ln x^{2} at the point (1,0) (1,0) .


A) y=2x2y=2 x-2
B) y=x1y=x-1
C) y=1x(x1) y=\frac{1}{x}(x-1)
D) y=2x(x1) y=\frac{2}{x}(x-1)

Correct Answer:

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