Suppose We Take a Disk of Radius $R$ And Remove the Material From

Multiple Choice

Suppose we take a disk of radius $R$ and remove the material from $r=0$ to $r=\frac{1}{2} R$ , making a hole at the center of the disk. Note that this decreases the mass of the disk. Will the value of $\alpha$ for the new object be larger, smaller, or the same as that for the original object?

A) The value of $\alpha$ will be larger for the new object.
B) The value of $\alpha$ will be smaller for the new object.
C) The value of $\alpha$ is the same for both objects.
D) We need to know the disk's thickness to answer.