Physically, Why Is a Gas Molecule's Speed $v$ More Likely to Be Near

Multiple Choice

Physically, why is a gas molecule's speed $v$ more likely to be near $v_{p}$ than near $2 v_{p}$ ?

A) There are fewer quantum states for larger speeds than there are at speeds near $v_{p}$ .
B) The Boltzmann factor is larger at $\mathbf{v}_{\mathbf{p}}$ than at $\mathbf{2} \mathbf{v}_{\mathbf{p}}$ .
C) We know that $\frac{1}{2} m\left[v^{2}\right]_{\text {avg }}=\frac{3}{2} k_{B} T$ , and $\mathrm{v}_{\mathrm{p}}$ is closer to $\left[v_{\text {avg }}^{2}\right]^{1 / 2}$ than $2 \mathrm{v}_{\mathrm{p}}$ is.