menu-iconExamlexExamLexServices

Discover

Ask a Question
  1. All Topics
  2. Topic
    Mathematics
  3. Study Set
    Technical Mathematics
  4. Exam
    Exam 7: Right Triangles and Vectors
  5. Question
    The Angle of Elevation from an Observer on the Ground\(408 \mathrm{~m}\)
Solved

The Angle of Elevation from an Observer on the Ground 408 m408 \mathrm{~m}408 m

Question 79

Question 79

Short Answer

The angle of elevation from an observer on the ground to the top of a 408 m408 \mathrm{~m}408 m high building is 38.3∘38.3^{\circ}38.3∘ . How far is the observer from the bottom of the building?
 The angle of elevation from an observer on the ground to the top of a  408 \mathrm{~m}  high building is  38.3^{\circ} . How far is the observer from the bottom of the building?

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q74: Find arcsec 16.8 in degrees to 4

Q75: Convert <span class="ql-formula" data-value="209.6^{\circ}"><span class="katex"><span

Q76: Determine the <span class="ql-formula" data-value="x"><span

Q77: Vector <span class="ql-formula" data-value="\mathbf{A}"><span class="katex"><span

Q78: The point <span class="ql-formula" data-value="(6,8)"><span

Q80: If <span class="ql-formula" data-value="\mathbf{V}_{\mathrm{x}}=2275"><span class="katex"><span

Q81: Convert <span class="ql-formula" data-value="49^{\circ} 16^{\prime}

Q82: Determine the value of <span

Q83: Solve the right triangle <span

Q84: If <span class="ql-formula" data-value="\tan \theta=1.428"><span

Examlex

ExamLex

About UsContact UsPerks CenterHomeschoolingTest Prep

Work With Us

Campus RepresentativeInfluencers

Links

FaqPricingChrome Extension

Download The App

Get App StoreGet Google Play

Policies

Privacy PolicyTerms of ServiceHonor CodeCommunity Guidelines

Scan To Download

qr-code

Copyright © (2025) ExamLex LLC.

Privacy PolicyTerms Of ServiceHonor CodeCommunity Guidelines