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    Exam 10: Systems of Linear Equations
  5. Question
    Solve\(x+z=35\) \(x+y=25\) \(y+z=32\)
Solved

Solve x+z=35x+z=35x+z=35 x+y=25x+y=25x+y=25 y+z=32y+z=32y+z=32

Question 20

Question 20

Short Answer

Solve: x+z=35x+z=35x+z=35
x+y=25x+y=25x+y=25
y+z=32y+z=32y+z=32

Correct Answer:

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