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Solve Leave Your Answers in Fractional Form x3+y2+z4=1\frac{x}{3}+\frac{y}{2}+\frac{z}{4}=1 2x+3y+2z=4x+y3+z2=2\begin{array}{r}2 x+3 y+2 z=4 \\x+\frac{y}{3}+\frac{z}{2}=2\end{array}

Question 40

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Solve. Leave your answers in fractional form: x3+y2+z4=1\frac{x}{3}+\frac{y}{2}+\frac{z}{4}=1
2x+3y+2z=4x+y3+z2=2\begin{array}{r}2 x+3 y+2 z=4 \\x+\frac{y}{3}+\frac{z}{2}=2\end{array}

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