Kirchhoff's Rules Were Applied to a Three-Loop Network $l_{1}, l_{2}$ , And

Short Answer

Kirchhoff's rules were applied to a three-loop network. Solve for currents $l_{1}, l_{2}$ , and $l_{3}$ in this resulting system of equations:
$76.0 I_{1}-25.0 I_{2}-50.0 I_{3}=10.0$
$-25.0 l_{1}+56.0 I_{2}-1.00 I_{3}=0.00$
$-50.0 l_{1}-1.0 I_{2}+106 l_{3}=0.00$