Solve by Determinants $x+2 z-w+u=1$ $3 y+z+2 w+u=-2$ $\begin{array}{r}-x-2 y-2 z+3 w+u=15 \\x+3 z-w+u=2.5\end{array}$

Essay

Solve by determinants: $x+2 z-w+u=1$
$3 y+z+2 w+u=-2$
$\begin{array}{r}-x-2 y-2 z+3 w+u=15 \\x+3 z-w+u=2.5\end{array}$
$x+y+z+w+u=1$