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The Force in Newtons on the Skier Shown Below Is F=mgcosθF=m g \cos \theta

Question 45

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The force in Newtons on the skier shown below is given by F=mgcosθF=m g \cos \theta where mm is the skier's mass in kilograms, g=9.8 m/s2g=9.8 \mathrm{~m} / \mathrm{s}^{2} is the acceleration due to gravity, and θ\theta is the angle the slope makes with the horizontal. Calculate the value of FF if m=80.0 kgm=80.0 \mathrm{~kg} and θ=30.0\theta=30.0^{\circ} .
 The force in Newtons on the skier shown below is given by  F=m g \cos \theta  where  m  is the skier's mass in kilograms,  g=9.8 \mathrm{~m} / \mathrm{s}^{2}  is the acceleration due to gravity, and  \theta  is the angle the slope makes with the horizontal. Calculate the value of  F  if  m=80.0 \mathrm{~kg}  and  \theta=30.0^{\circ} .

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