If the Power Input Is $P_{1}$ And the Power Output Is $P_{2}$

Short Answer

If the power input is $P_{1}$ and the power output is $P_{2}$ , the number of decibels gained or lost is $G=10 \log \frac{P_{2}}{P_{1}}$ (dB). If the amplifier gains $15.0 \mathrm{~dB}$ for an input of $90.0 \mathrm{~W}$ , find the power output.