Divide $12\left(\cos 22^{\circ}+j \sin 22^{\circ}\right)$ By $3\left(\cos 12^{\circ}+j \sin 12^{\circ}\right)$

Short Answer

Divide: $12\left(\cos 22^{\circ}+j \sin 22^{\circ}\right)$ by $3\left(\cos 12^{\circ}+j \sin 12^{\circ}\right)$