Find the Point(s) of Intersection $x^{2}+y^{2}-14 y-51=0$ And $x^{2}+y^{2}+20 x-36 y+399=0$

Short Answer

Find the point(s) of intersection: $x^{2}+y^{2}-14 y-51=0$ and $x^{2}+y^{2}+20 x-36 y+399=0$