Find the Point(s) of Intersection $x^{2}+y^{2}+2 x-2 y-23=0$ And $x^{2}+y^{2}-6 x+12 y-35=0$

Short Answer

Find the point(s) of intersection: $x^{2}+y^{2}+2 x-2 y-23=0$ and $x^{2}+y^{2}-6 x+12 y-35=0$