Find the Point(s) of Intersection $x^{2}+y^{2}-4 x+2 y-4=0$ And $x^{2}+y^{2}+2 x-4 y-11=0$

Short Answer

Find the point(s) of intersection: $x^{2}+y^{2}-4 x+2 y-4=0$ and $x^{2}+y^{2}+2 x-4 y-11=0$