A Rocket Fired At $275 \mathrm{~m} / \mathrm{s}$ At $36^{\circ}$ Angle of Elevation Is Described By

Short Answer

A rocket fired at $275 \mathrm{~m} / \mathrm{s}$ at $36^{\circ}$ angle of elevation is described by $x=\left(275 \cos 36^{\circ}\right) t$ and $y=\left(275 \sin 36^{\circ}\right) t-4.9 t^{2}$ . Find the velocity (magnitude and direction) at $8 \mathrm{~s}$ .