The End of a Robotic Arm Follows the Displacement Equation $s=2 t^{3}-3 t^{2}+t-3$

Short Answer

The end of a robotic arm follows the displacement equation $s=2 t^{3}-3 t^{2}+t-3$ where $\mathrm{s}$ is in $\mathrm{mm}$ . What is the acceleration at the end of the arm after $1.5 \mathrm{~s}$ ?