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A Circular Plate Is Cooled and Contracts So Its Radius $0.01 \mathrm{~cm} / \mathrm{s}$

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A circular plate is cooled and contracts so its radius is shrinking by $0.01 \mathrm{~cm} / \mathrm{s}$ . How fast is the area of one face decreasing when the radius is $2.5 \mathrm{~cm}$ ?

A Circular Plate Is Cooled and Contracts So Its Radius 0.01 cm/s0.01 \mathrm{~cm} / \mathrm{s}0.01 cm/s

Short Answer

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A Circular Plate Is Cooled and Contracts So Its Radius $0.01 \mathrm{~cm} / \mathrm{s}$

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