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Solve the Problem d=12gt2\mathrm{d}=\frac{1}{2} \mathrm{gt}^{2} , Where g\mathrm{g} Is About 32ft/sec232 \mathrm{ft} / \mathrm{sec}^{2}

Question 243

Multiple Choice

Solve the problem.
-If an object is dropped, the distance it falls is given by d=12gt2\mathrm{d}=\frac{1}{2} \mathrm{gt}^{2} , where g\mathrm{g} is about 32ft/sec232 \mathrm{ft} / \mathrm{sec}^{2} . Find the distance an object would fall in 6 seconds.


A) 576ft576 \mathrm{ft}
B) 1152ft1152 \mathrm{ft}
C) 96ft96 \mathrm{ft}
D) 288ft288 \mathrm{ft}

Correct Answer:

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