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Solve the Formula for the Specified Variable F=95C+32\mathrm{F}=\frac{9}{5} \mathrm{C}+32 For C\mathrm{C} A) C=5F32C=\frac{5}{F-32}

Question 119

Multiple Choice

Solve the formula for the specified variable.
- F=95C+32\mathrm{F}=\frac{9}{5} \mathrm{C}+32 for C\mathrm{C}


A) C=5F32C=\frac{5}{F-32}
B) C=F329\mathrm{C}=\frac{\mathrm{F}-32}{9}
C) C=59( F32) \mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)
D) C=95( F32) \mathrm{C}=\frac{9}{5}(\mathrm{~F}-32)

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