Solve the Inequality $12 k^{3}-16 k^{2} \leq 3 k$ A) $\left(-\infty,-\frac{1}{6}\right]$ Or $\left[0, \frac{3}{2}\right]$

Multiple Choice

Solve the inequality.
- $12 k^{3}-16 k^{2} \leq 3 k$

A) $\left(-\infty,-\frac{1}{6}\right]$ or $\left[0, \frac{3}{2}\right]$
B) $\left(-\infty,-\frac{1}{6}\right)$ or $\left(0, \frac{3}{2}\right)$
C) $\left\{-\infty,-\frac{1}{6}\right]$ or $\left[0, \frac{3}{2}\right)$
D) $\left\{-\infty,-\frac{1}{6}\right)$ or $\left[0, \frac{3}{2}\right]$