Solve the Problem $d(t)=6\left(1-\frac{t}{12}\right)^{2}$ Meters If the Valve Is Opened At from a Tank

Multiple Choice

Solve the problem.
-The water is drained from a tank by opening a valve at the bottom of the tank. The depth of the water in the tank thours after the valve is opened is $d(t) =6\left(1-\frac{t}{12}\right) ^{2}$ meters. If the valve is opened at $1 \mathrm{pm}$ , what is the depth of water at $10 \mathrm{pm}$ ?

A) 2.62 meters
B) 1.50 meters
C) 0.38 meters
D) 0.17 meters