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    Exam 4: Exponential and Logarithmic Functions
  5. Question
    Solve the Equation\(2 \mathrm{e}^{2 \mathrm{x}-5}=10\) A) -1695 B) 7
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Solve the Equation 2e2x−5=102 \mathrm{e}^{2 \mathrm{x}-5}=102e2x−5=10 A) -1695
B) 7

Question 171

Question 171

Multiple Choice

Solve the equation.
- 2e2x−5=102 \mathrm{e}^{2 \mathrm{x}-5}=102e2x−5=10


A) -1.695
B) 7.500
C) 3.076
D) 3.305

Correct Answer:

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