Find$f[g(x)]$ And$g[f(x)]$
-$\mathrm{f}(\mathrm{x})=\frac{2}{\mathrm{x}} ; \mathrm{g}(\mathrm{x})=2 \mathrm{x}^{3}$ A)$f[g(x)]=4 / x^{3} ; g[f(x)]=1 / x^{3}$

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Find$f[g(x)]$ And$g[f(x)]$  
-$\mathrm{f}(\mathrm{x})=\frac{2}{\mathrm{x}} ; \mathrm{g}(\mathrm{x})=2 \mathrm{x}^{3}$ A)$f[g(x)]=4 / x^{3} ; g[f(x)]=1 / x^{3}$

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The Answer of Find$f[g(x)]$ And$g[f(x)]$  
-$\mathrm{f}(\mathrm{x})=\frac{2}{\mathrm{x}} ; \mathrm{g}(\mathrm{x})=2 \mathrm{x}^{3}$ A)$f[g(x)]=4 / x^{3} ; g[f(x)]=1 / x^{3}$

Find $f[g(x)]$ And $g[f(x)]$
- $\mathrm{f}(\mathrm{x})=\frac{2}{\mathrm{x}} ; \mathrm{g}(\mathrm{x})=2 \mathrm{x}^{3}$ A) $f[g(x)]=4 / x^{3} ; g[f(x)]=1 / x^{3}$

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Find f[g(x)]f[g(x)]f[g(x)] And g[f(x)]g[f(x)]g[f(x)] - f(x)=2x;g(x)=2x3\mathrm{f}(\mathrm{x})=\frac{2}{\mathrm{x}} ; \mathrm{g}(\mathrm{x})=2 \mathrm{x}^{3}f(x)=x2​;g(x)=2x3 A) f[g(x)]=4/x3;g[f(x)]=1/x3f[g(x)]=4 / x^{3} ; g[f(x)]=1 / x^{3}f[g(x)]=4/x3;g[f(x)]=1/x3

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Find $f[g(x)]$ And $g[f(x)]$
- $\mathrm{f}(\mathrm{x})=\frac{2}{\mathrm{x}} ; \mathrm{g}(\mathrm{x})=2 \mathrm{x}^{3}$ A) $f[g(x)]=4 / x^{3} ; g[f(x)]=1 / x^{3}$

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