Find Functions $g$ And $h$ Such That $f(x)=g(h(x))$
- $f(x)=\frac{1}{x^{2}-6}$ A) $g(x)=\frac{1}{x^{2}}, h(x)=-1 / 6$

Multiple Choice

Find functions $g$ and $h$ such that $f(x) =g(h(x) )$ .
- $f(x) =\frac{1}{x^{2}-6}$

A) $g(x) =\frac{1}{x^{2}}, h(x) =-1 / 6$
B) $g(x) =1 / 6, h(x) =x^{2}-6$
C) $g(x) =\frac{1}{x^{2}}, h(x) =x-6$
D) $g(x) =\frac{1}{x}, h(x) =x^{2}-6$