Solved

Solve the Problem tt Seconds Is Given By s(t)=16t2s(t)=-16 t^{2} , Where Negative Distance (Or Velocity) Indicates Downward Motion

Question 58

Multiple Choice

Solve the problem.
-When an object is dropped straight down, the distance in feet that it falls in tt seconds is given by s(t) =16t2s(t) =-16 t^{2} , where negative distance (or velocity) indicates downward motion. Find the velocity and acceleration at t=8\mathrm{t}=8 .


A) Velocity =32ft/sec=-32 \mathrm{ft} / \mathrm{sec} ; acceleration =0ft/sec2=0 \mathrm{ft} / \mathrm{sec}^{2}
B) Velocity =256ft/sec=-256 \mathrm{ft} / \mathrm{sec} ; acceleration =32ft/sec2=-32 \mathrm{ft} / \mathrm{sec}^{2}
C) Velocity =32ft/sec=-32 \mathrm{ft} / \mathrm{sec} ; acceleration =256ft/sec2=-256 \mathrm{ft} / \mathrm{sec}^{2}
D) Velocity =256ft/sec=-256 \mathrm{ft} / \mathrm{sec} ; acceleration =0ft/sec2=0 \mathrm{ft} / \mathrm{sec}^{2}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions