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Find the Equation of the Tangent Line at the Given xy2=12;(3,2)x y^{2}=12 ;(3,-2)

Question 141

Multiple Choice

Find the equation of the tangent line at the given point on the curve.
- xy2=12;(3,2) x y^{2}=12 ;(3,-2)


A) y=13x3y=-\frac{1}{3} x-3
B) y=13x3y=\frac{1}{3} x-3
C) y=13x+3y=\frac{1}{3} x+3
D) y=13x+3y=-\frac{1}{3} x+3

Correct Answer:

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