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Solve the Problem m=132.9w0.75\mathrm{m}=132.9 \mathrm{w} 0.75 , Where w\mathrm{w} Is the Weight of the Hippopotamus (In

Question 156

Multiple Choice

Solve the problem.
-The average daily metabolic rate for a hippopotamus living in the wild can be expressed as a function of weight by m=132.9w0.75\mathrm{m}=132.9 \mathrm{w} 0.75 , where w\mathrm{w} is the weight of the hippopotamus (in kg\mathrm{kg} ) and m\mathrm{m} is the metabolic rate (in kcal/day\mathrm{kcal} / \mathrm{day} ) . Determine dm/dt\mathrm{dm} / \mathrm{dt} for a 2100kg2100-\mathrm{kg} hippopotamus that is gaining weight at a rate of 15.75 kg/15.75 \mathrm{~kg} / day.


A) 309kcal/day2309 \mathrm{kcal} / \mathrm{day}^{2}
B) 232kcal/day2232 \mathrm{kcal} / \mathrm{day}^{2}
C) 15kcal/day215 \mathrm{kcal} / \mathrm{day}^{2}
D) 10,627kcal/day210,627 \mathrm{kcal} / \mathrm{day}^{2}

Correct Answer:

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