Solve the Problem $\frac{d y}{d t}=6000 e^{.06 t}$ , Where $y$ Is the Population at Time

Multiple Choice

Solve the problem.
-Assume that the rate of change of the population of a certain city is given by $\frac{d y}{d t}=6000 e^{.06 t}$ , where $y$ is the population at time $t$ , in years. The population was 100,000 in 1980. Assume $t=0$ is 1980. Find the population function.

A) $y=100,000 e^{.06 t}$
B) $y=100,000 e \cdot 06$
C) $y=10,000 e^{.06 t}+90,000$
D) $y=1,000,000 e^{.06}+900,000$