Solve the Problem $\frac{d y}{d t}=6000 e^{.06 t}$ , Where $y$ Is the Population at Time

Multiple Choice

Solve the problem.
-Assume that the rate of change of the population of a certain city is given by $\frac{d y}{d t}=6000 e^{.06 t}$ , where $y$ is the population at time $t$ , in years. The population was 100,000 in 1980 . Assume $t=0$ is 1980. Predict the population in 1990 .

A) $1.8 \times 10^{5}$
B) $1.9 \times 10^{5}$
C) $9.2 \times 10^{5}$
D) $1.1 \times 10^{5}$