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If the Absolute Magnitude, M, of a Supernova Is −19 10(m−M+5)/510^{(m - M + 5)/5}

Question 113

Multiple Choice

If the absolute magnitude, M, of a supernova is −19 and a galaxy is found that contains a supernova with an apparent magnitude, m, of 16. What is the distance to the galaxy Hint: dpc = 10(m−M+5) /510^{(m - M + 5) /5}


A) 100 AU
B) 100 pc
C) 100 ly
D) 100 kpc
E) 100 Mpc

Correct Answer:

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