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Mycobacterium Fortuitum, M.chelonae, and M.abscessus Are

Question 39

Multiple Choice

Mycobacterium fortuitum, M.chelonae, and M.abscessus are:


A) responsible for approximately 90% of clinical mycobacterial disease.
B) unable to grow on routine bacteriologic media.
C) gram-negative rods resembling Escherichia coli on Gram stain.
D) slow growers requiring a minimum of 14 days to grow.

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