NADH + H⁺ Has More Reducing Power Than FADH₂, Therefore $\Delta$

Multiple Choice

NADH + H⁺ has more reducing power than FADH₂, therefore:

A) oxidation of NADH will contribute to form a larger $\Delta$ p and more ATP
B) oxidation of FADH₂ by respiratory ETS contributes less to $\Delta$ p formation, and as a consequence fewer ATP can be made
C) the NADH + H⁺/NAD⁺ redox pair has a more negative E°' value than the FAD/FADH₂ pair
D) all of the above
E) none of the above