Multiple Choice
A proton that is initially at rest is accelerated through an electric potential difference of magnitude 500 V.How much kinetic energy does it gain? (e = 1.60 × 10-19C)
A) 500 J
B) 8.0 × 10-17 J
C) 1.6 × 10-19 J
D) 800 J
Correct Answer:
Verified
Correct Answer:
Verified
Related Questions
Q76: A parallel-plate capacitor is connected to a
Q77: A 5.0 μF capacitor has a potential
Q78: When the magnitude of the charge on
Q79: Two 3.0 μC charges lie on the
Q80: In a region where the electric field
Q82: A region of space contains a uniform
Q83: Each plate of an ideal air-filled parallel-plate
Q84: What charge accumulates on the plates of
Q85: An ideal parallel-plate capacitor consists of two
Q86: If the result of your calculation of