Multiple Choice
A proton with a speed of 2.0 x
M/s accelerates through a potential difference and thereby increases its speed to 4.0 ×
M/s.Through what magnitude potential difference did the proton accelerate?
,mproton = 1.67 × 10-27 kg)
A) 630 V
B) 210 V
C) 840 V
D) 1,000 V
E) 100 V
Correct Answer:

Verified
Correct Answer:
Verified
Related Questions
Q4: Two protons are released from rest,with only
Q5: Consider a uniform horizontal electric field of
Q6: An air-filled 20-μF capacitor has a charge
Q7: If you want to store 2.0 mJ
Q8: Point charges +4.00 μC and +2.00 μC
Q10: When a 4-μF capacitor has a potential
Q11: Four 2.0-µC point are at the corners
Q12: A uniform electric field,with a magnitude of
Q13: A capacitor has a voltage of <img
Q14: Four charged particles (two having a charge