Multiple Choice
In rabbits,spotted coat (S) is dominant to solid color (s) and black (B) is dominant to brown (b) .A true-breeding black spotted rabbit is mated to a true-breeding brown solid rabbit to produce a heterozygous F1 generation.Two F1 individuals are mated,and you do not see a 9:3:3:1 (black spotted: black solid: brown spotted: brown solid) ratio of offspring,but instead see that almost all offspring are a non-recombinant phenotype.This tells you that
A) that the genes for fur pattern (spotted vs.non-spotted) and fur color assort independently
B) that the genes for fur pattern (spotted vs.non-spotted) and fur color are on the same chromosome
C) that the genes for fur pattern (spotted vs.non-spotted) and fur color are on different chromosomes
D) that the genes for fur pattern (spotted vs.non-spotted) and fur color are on the X-chromosome and Y-chromosome,repectively.
E) that fur pattern (spotted vs.non-spotted) and fur color are maternally inherited
Correct Answer:

Verified
Correct Answer:
Verified
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