When $\begin{array} { c } 226 \\88\end{array}$ Ra Decays by Emitting an Alpha Particle,what Is the Atomic

Multiple Choice

When $\begin{array} { c } 226 \\88\end{array}$ Ra decays by emitting an alpha particle,what is the atomic number of the resulting nucleus? What is the resulting atomic mass?

A) atomic number = 86; atomic mass = 222
B) atomic number = 87; atomic mass = 226
C) atomic number = 86; atomic mass = 224
D) atomic number = 87; atomic mass = 224