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A Clinic Has Four Doctors  Kruskal-Wallis Test \text { Kruskal-Wallis Test }

Question 18

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A clinic has four doctors. They wish to compare the amount of time that doctors spend with their patients. It is suspected that times may not be normally distributed but are otherwise assumed similar except in center, so a nonparametric test was chosen. The Kruskal-Wallis test results are shown below.  Kruskal-Wallis Test \text { Kruskal-Wallis Test }
 Wedian n Avg. Rank 27.001119.18 Doc A 28.501415.93 Doc B 46.00936.39 Doc C 31.001124.86 Doc D 31.0045 Total \begin{array}{ccrl}\hline \text { Wedian } & n & \text { Avg. Rank } & \\\hline 27.00 & 11 & 19.18 & \text { Doc A } \\28.50 & 14 & 15.93 & \text { Doc B } \\46.00 & 9 & 36.39 & \text { Doc C } \\31.00 & 11 & 24.86 & \text { Doc D } \\\hline 31.00 & 45 & & \text { Total }\end{array}
14.599 H \mathrm{H} (corrected for ties)
3 d.f.
, 0022 p-value Which is the best conclusion?


A) The doctors have the same median times at ? = .01.
B) The doctors have different median times at ? = .01.
C) The sample size is insufficient for this kind of test.
D) A one-factor ANOVA would be a better kind of test.

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