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The Number of Ways to Arrange X Successes Among N n!x!(nx)!\frac { n ! } { x ! ( n - x ) ! }

Question 95

Multiple Choice

The number of ways to arrange x successes among n trials is equal to


A) n!x!(nx) !\frac { n ! } { x ! ( n - x ) ! }
B) n!(nx) !\frac { n ! } { ( n - x ) ! }
C) n/xn / x
D) n!/x!n ! /x!

Correct Answer:

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